What are the solutions to the equation x^3-1=-x+9 ?

The solutions to the equation x^3-1=-x+9 are x=2,x=-1+2i,x=-1-2i

Find the zeros of x^3-1=-x+9

The zeros of x^3-1=-x+9 are x=2,x=-1+2i,x=-1-2i

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x^{3} - 1 = - x + 9

x = 2, x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

x^{3} - 1 = - x + 9

Move

9

to the left side

x^{3} - 10 = - x

Move

x

to the left side

x^{3} - 10 + x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} + x - 10 = 0

Factor

x^{3} + x - 10 : (x - 2) (x^{2} + 2 x + 5)

(x - 2) (x^{2} + 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 2 x + 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 5 = 0 : x = - 1 + 2 i, x = - 1 - 2 i

The solutions are

x = 2, x = - 1 + 2 i, x = - 1 - 2 i

7 x^{6} - 42 x^{5} = 0

8 x^{5} = 32768 x

(2 + x)^{3} - 2 = 2.8 + (- 3)^{2}

2 x^{3} - 3 x^{2} - 23 x + 12 = 0

4 = x^{5} + 2 x + 1

What are the solutions to the equation x^3-1=-x+9 ?
The solutions to the equation x^3-1=-x+9 are x=2,x=-1+2i,x=-1-2i
Find the zeros of x^3-1=-x+9
The zeros of x^3-1=-x+9 are x=2,x=-1+2i,x=-1-2i