What are the solutions to the equation -λ^3+2λ^2+λ-2=0 ?

The solutions to the equation -λ^3+2λ^2+λ-2=0 are λ=2,λ=-1,λ=1

Find the zeros of -λ^3+2λ^2+λ-2=0

The zeros of -λ^3+2λ^2+λ-2=0 are λ=2,λ=-1,λ=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- λ^{3} + 2 λ^{2} + λ - 2 = 0

λ = 2, λ = - 1, λ = 1

Solution steps

- λ^{3} + 2 λ^{2} + λ - 2 = 0

Factor

- λ^{3} + 2 λ^{2} + λ - 2 : - (λ - 2) (λ + 1) (λ - 1)

- (λ - 2) (λ + 1) (λ - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ - 2 = 0 or λ + 1 = 0 or λ - 1 = 0

Solve

λ - 2 = 0 : λ = 2

Solve

λ + 1 = 0 : λ = - 1

Solve

λ - 1 = 0 : λ = 1

The solutions are

λ = 2, λ = - 1, λ = 1

9 x^{4} + 45 x^{2} + 14 = 0

x (x^{3} - x^{2}) - 4 x^{2} - x^{1} = 0

418.879 = 6 t + 0.11667 t^{3}

4 x^{4} = 2048 x

x^{4} - 145 x^{2} + 144 = 0

What are the solutions to the equation -λ^3+2λ^2+λ-2=0 ?
The solutions to the equation -λ^3+2λ^2+λ-2=0 are λ=2,λ=-1,λ=1
Find the zeros of -λ^3+2λ^2+λ-2=0
The zeros of -λ^3+2λ^2+λ-2=0 are λ=2,λ=-1,λ=1