What are the solutions to the equation 3x^3-x-2=0 ?

The solutions to the equation 3x^3-x-2=0 are x=1,x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6

Find the zeros of 3x^3-x-2=0

The zeros of 3x^3-x-2=0 are x=1,x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6

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3 x^{3} - x - 2 = 0

x = 1, x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

Solution steps

3 x^{3} - x - 2 = 0

Factor

3 x^{3} - x - 2 : (x - 1) (3 x^{2} + 3 x + 2)

(x - 1) (3 x^{2} + 3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x^{2} + 3 x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x^{2} + 3 x + 2 = 0 : x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

The solutions are

x = 1, x = - \frac{1}{2} + i \frac{15}{6}, x = - \frac{1}{2} - i \frac{15}{6}

b^{3} + 3.31 = 0.41

30 x^{3} + 5 x^{2} - 25 x = 0

x, V = 2 x^{3} - 3 y^{3}

x^{3} - 70 x^{2} - 7125 x + 118750 = 0

2 y^{4} + 2 y^{3} - 24 y^{2} = 0

What are the solutions to the equation 3x^3-x-2=0 ?
The solutions to the equation 3x^3-x-2=0 are x=1,x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6
Find the zeros of 3x^3-x-2=0
The zeros of 3x^3-x-2=0 are x=1,x=-1/2+i(sqrt(15))/6 ,x=-1/2-i(sqrt(15))/6