What are the solutions to the equation (4x^2-25)^2=0 ?

The solutions to the equation (4x^2-25)^2=0 are x= 5/2 ,x=-5/2

Find the zeros of (4x^2-25)^2=0

The zeros of (4x^2-25)^2=0 are x= 5/2 ,x=-5/2

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(4 x^{2} - 25)^{2} = 0

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 2.5, x = - 2.5

Solution steps

(4 x^{2} - 25)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

4 x^{2} - 25 = 0 : x = \frac{5}{2}, x = - \frac{5}{2}

The solutions are

x = \frac{5}{2}, x = - \frac{5}{2}

4 x^{3} - 3 = 9

x^{3} - 4 x^{2} - 9 x = - 36

15 x^{4} - 6 0^{2} = 0

3 x^{3} + 5 x^{2} - 63 x - 1 = 0

- x^{3} + 14 x - 12 = 0

What are the solutions to the equation (4x^2-25)^2=0 ?
The solutions to the equation (4x^2-25)^2=0 are x= 5/2 ,x=-5/2
Find the zeros of (4x^2-25)^2=0
The zeros of (4x^2-25)^2=0 are x= 5/2 ,x=-5/2