What are the solutions to the equation (x-2)(x+3)(x-5)=0 ?

The solutions to the equation (x-2)(x+3)(x-5)=0 are x=2,x=-3,x=5

Find the zeros of (x-2)(x+3)(x-5)=0

The zeros of (x-2)(x+3)(x-5)=0 are x=2,x=-3,x=5

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(x - 2) (x + 3) (x - 5) = 0

x = 2, x = - 3, x = 5

Solution steps

(x - 2) (x + 3) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 3 = 0 or x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 5 = 0 : x = 5

The solutions are

x = 2, x = - 3, x = 5

x^{5} - 10 x^{3} + 9 x = 0

p^{6} = 6

x^{4} + 3 x - 4 = 0

(z^{2} + 1)^{2} = 0

(1 - x) ((3 - x) (1 - x) + 1) = 0

What are the solutions to the equation (x-2)(x+3)(x-5)=0 ?
The solutions to the equation (x-2)(x+3)(x-5)=0 are x=2,x=-3,x=5
Find the zeros of (x-2)(x+3)(x-5)=0
The zeros of (x-2)(x+3)(x-5)=0 are x=2,x=-3,x=5