What are the solutions to the equation 2=(2x^7)/7 ?

The solutions to the equation 2=(2x^7)/7 are x=\sqrt[7]{7}

Find the zeros of 2=(2x^7)/7

The zeros of 2=(2x^7)/7 are x=\sqrt[7]{7}

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2 = \frac{2 x ^{7}}{7}

Decimal Notation

x = 1.32046 \dots

Solution steps

2 = \frac{2 x ^{7}}{7}

Switch sides

\frac{2 x ^{7}}{7} = 2

Multiply both sides by

7

2 x^{7} = 14

Divide both sides by

2

x^{7} = 7

For

x^{n} = f (a)

, n is odd, the solution is

y^{4} + y^{2} = 0

x = x^{3} + 2

x, y^{4} - x^{3} = 1

0 = x^{3} + 2 x^{2}

x^{3} - 3 x + 2 = 12

What are the solutions to the equation 2=(2x^7)/7 ?
The solutions to the equation 2=(2x^7)/7 are x=\sqrt[7]{7}
Find the zeros of 2=(2x^7)/7
The zeros of 2=(2x^7)/7 are x=\sqrt[7]{7}