What are the solutions to the equation 9x^3+13x-2022=0 ?

The solutions to the equation 9x^3+13x-2022=0 are x=6,x=-3+i 16/3 ,x=-3-i 16/3

Find the zeros of 9x^3+13x-2022=0

The zeros of 9x^3+13x-2022=0 are x=6,x=-3+i 16/3 ,x=-3-i 16/3

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9 x^{3} + 13 x - 2022 = 0

x = 6, x = - 3 + i \frac{16}{3}, x = - 3 - i \frac{16}{3}

Solution steps

9 x^{3} + 13 x - 2022 = 0

Factor

9 x^{3} + 13 x - 2022 : (x - 6) (9 x^{2} + 54 x + 337)

(x - 6) (9 x^{2} + 54 x + 337) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or 9 x^{2} + 54 x + 337 = 0

Solve

x - 6 = 0 : x = 6

Solve

9 x^{2} + 54 x + 337 = 0 : x = - 3 + i \frac{16}{3}, x = - 3 - i \frac{16}{3}

The solutions are

x = 6, x = - 3 + i \frac{16}{3}, x = - 3 - i \frac{16}{3}

2 x^{3} + x^{2} + 1 = 0

x^{4} + 3 x^{2} - 1 = 0

n^{2} = \frac{n ( n + 1 ) ( 2 n + 1 )}{6}

x^{4} - 34 x^{2} + 255 = 0

4 x^{3} + 2 x - 6 = 0

What are the solutions to the equation 9x^3+13x-2022=0 ?
The solutions to the equation 9x^3+13x-2022=0 are x=6,x=-3+i 16/3 ,x=-3-i 16/3
Find the zeros of 9x^3+13x-2022=0
The zeros of 9x^3+13x-2022=0 are x=6,x=-3+i 16/3 ,x=-3-i 16/3