What are the solutions to the equation z^5=-32+0i ?

The solutions to the equation z^5=-32+0i are z=-2

Find the zeros of z^5=-32+0i

The zeros of z^5=-32+0i are z=-2

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z^{5} = - 32 + 0 i

z = - 2

Solution steps

z^{5} = - 32 + 0 i

Simplify

- 32 + 0 i : - 32

For

x^{n} = f (a)

, n is odd, the solution is

z = - 2

x^{3} + x^{2} = 12

x^{3} - 3 = 53 x + 2

r^{4} - 1 = 0

x^{4} - 4 x^{3} - 5 x^{2} = 0

x^{3} + 2 x^{2} - 5 x - 2 = 0

What are the solutions to the equation z^5=-32+0i ?
The solutions to the equation z^5=-32+0i are z=-2
Find the zeros of z^5=-32+0i
The zeros of z^5=-32+0i are z=-2