What are the solutions to the equation (2s^2-1)^2=225 ?

The solutions to the equation (2s^2-1)^2=225 are s=2sqrt(2),s=-2sqrt(2),s=sqrt(7)i,s=-sqrt(7)i

Find the zeros of (2s^2-1)^2=225

The zeros of (2s^2-1)^2=225 are s=2sqrt(2),s=-2sqrt(2),s=sqrt(7)i,s=-sqrt(7)i

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(2 s^{2} - 1)^{2} = 225

s = 22, s = - 22, s = 7 i, s = - 7 i

Solution steps

(2 s^{2} - 1)^{2} = 225

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 s^{2} - 1 = 225 : s = 22, s = - 22

Solve

2 s^{2} - 1 = - 225 : s = 7 i, s = - 7 i

The solutions are

s = 22, s = - 22, s = 7 i, s = - 7 i

a^{3} + a^{2} = a^{5}

x^{4} + 36 = 13 x^{2}

x^{3} + x + 3 = x^{2}

x^{2} = 14 x^{6}

q^{4} - q^{2} - 6 = 0

What are the solutions to the equation (2s^2-1)^2=225 ?
The solutions to the equation (2s^2-1)^2=225 are s=2sqrt(2),s=-2sqrt(2),s=sqrt(7)i,s=-sqrt(7)i
Find the zeros of (2s^2-1)^2=225
The zeros of (2s^2-1)^2=225 are s=2sqrt(2),s=-2sqrt(2),s=sqrt(7)i,s=-sqrt(7)i