What are the solutions to the equation (1+x/(12))^{12}=1.08 ?

The solutions to the equation (1+x/(12))^{12}=1.08 are x=0.07720…,x=-24.07720…

Find the zeros of (1+x/(12))^{12}=1.08

The zeros of (1+x/(12))^{12}=1.08 are x=0.07720…,x=-24.07720…

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(1 + \frac{x}{12})^{12} = 1.08

x = 0.07720 \dots, x = - 24.07720 \dots

Solution steps

(1 + \frac{x}{12})^{12} = 1.08

For

(g (x))^{n} = f (a)

, n is even, the solutions are

Solve

The solutions are

x = 0.07720 \dots, x = - 24.07720 \dots

u^{3} + 8 = (u + 2)

- 6 + w^{3} = - 9

54 = (6 - p^{4}) 3

y, x = 1 + (y - 2)^{3}

(x^{2} - 8)^{2} - 2 (x^{2} - 8) = - 1

What are the solutions to the equation (1+x/(12))^{12}=1.08 ?
The solutions to the equation (1+x/(12))^{12}=1.08 are x=0.07720…,x=-24.07720…
Find the zeros of (1+x/(12))^{12}=1.08
The zeros of (1+x/(12))^{12}=1.08 are x=0.07720…,x=-24.07720…