What are the solutions to the equation 4x^3-6x^2-18x+27=0 ?

The solutions to the equation 4x^3-6x^2-18x+27=0 are x= 3/2 ,x=-3/(sqrt(2)),x= 3/(sqrt(2))

Find the zeros of 4x^3-6x^2-18x+27=0

The zeros of 4x^3-6x^2-18x+27=0 are x= 3/2 ,x=-3/(sqrt(2)),x= 3/(sqrt(2))

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4 x^{3} - 6 x^{2} - 18 x + 27 = 0

x = \frac{3}{2}, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = 1.5, x = - 2.12132 \dots, x = 2.12132 \dots

Solution steps

4 x^{3} - 6 x^{2} - 18 x + 27 = 0

Factor

4 x^{3} - 6 x^{2} - 18 x + 27 : (2 x - 3) (2 x + 3) (2 x - 3)

(2 x - 3) (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = \frac{3}{2}, x = - \frac{3}{2}, x = \frac{3}{2}

x^{3} + 9 x - 6 = 0

- x^{4} + 2 x^{3} + x^{2} - 4 x + 2 = 0

x^{4} - x^{3} - 8 x^{2} - 4 x - 48 = 0

x^{3} - 3 x - 1.9 = 0

(x^{2} + 1) + (x^{2} + 1) (x^{4} + 1) = 0

What are the solutions to the equation 4x^3-6x^2-18x+27=0 ?
The solutions to the equation 4x^3-6x^2-18x+27=0 are x= 3/2 ,x=-3/(sqrt(2)),x= 3/(sqrt(2))
Find the zeros of 4x^3-6x^2-18x+27=0
The zeros of 4x^3-6x^2-18x+27=0 are x= 3/2 ,x=-3/(sqrt(2)),x= 3/(sqrt(2))