What is (5*(3^2*10)^2)/(3^2*60^2) ?

The solution to (5*(3^2*10)^2)/(3^2*60^2) is 5/4

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simplify (5(3^210)^2)/(3^2*60^2)

simplify

\frac{5 \cdot ( 3 ^{2} \cdot 10 ) ^{2}}{3 ^{2} \cdot 6 0 ^{2}}

\frac{5}{4}

Solution steps

\frac{5 ( 3 ^{2} \cdot 10 ) ^{2}}{3 ^{2} \cdot 6 0 ^{2}}

Factor

6 0^{2} : 5^{2} \cdot 1 2^{2}

= \frac{5 ( 3 ^{2} \cdot 10 ) ^{2}}{3 ^{2} \cdot 5 ^{2} \cdot 1 2 ^{2}}

\frac{5}{5 ^{2}} = \frac{1}{5}

= \frac{( 3 ^{2} \cdot 10 ) ^{2}}{3 ^{2} \cdot 5 \cdot 1 2 ^{2}}

(3^{2} \cdot 10)^{2} = 81 \cdot 1 0^{2}

= \frac{81 \cdot 1 0 ^{2}}{3 ^{2} \cdot 5 \cdot 1 2 ^{2}}

Factor the number:

81 = 3^{4}

= \frac{3 ^{4} \cdot 1 0 ^{2}}{3 ^{2} \cdot 5 \cdot 1 2 ^{2}}

\frac{3 ^{4}}{3 ^{2}} = 3^{2}

= \frac{3 ^{2} \cdot 1 0 ^{2}}{5 \cdot 1 2 ^{2}}

Factor

1 2^{2} : 3^{2} \cdot 4^{2}

= \frac{3 ^{2} \cdot 1 0 ^{2}}{5 \cdot 3 ^{2} \cdot 4 ^{2}}

Cancel the common factor:

3^{2}

= \frac{1 0 ^{2}}{5 \cdot 4 ^{2}}

Factor

1 0^{2} : 5^{2} \cdot 2^{2}

= \frac{5 ^{2} \cdot 2 ^{2}}{5 \cdot 4 ^{2}}

\frac{5 ^{2}}{5} = 5

= \frac{5 \cdot 2 ^{2}}{4 ^{2}}

Factor

4^{2} : 2^{4}

= \frac{5 \cdot 2 ^{2}}{2 ^{4}}

\frac{2 ^{2}}{2 ^{4}} = \frac{1}{2 ^{2}}

= \frac{5}{2 ^{2}}

2^{2} = 4

= \frac{5}{4}

5 x^{2} = 6 x + 27

\frac{12 !}{10 ! ( 12 - 10 ) !}

x^{2} - x y + x - x y^{2} + y^{3} - y^{2}

3 w < 9

\frac{\frac{5}{13}}{\frac{12}{13}}

What is (5*(3^2*10)^2)/(3^2*60^2) ?
The solution to (5*(3^2*10)^2)/(3^2*60^2) is 5/4