What are the solutions to the equation x^3=2x+4 ?

The solutions to the equation x^3=2x+4 are x=2,x=-1+i,x=-1-i

Find the zeros of x^3=2x+4

The zeros of x^3=2x+4 are x=2,x=-1+i,x=-1-i

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x^{3} = 2 x + 4

x = 2, x = - 1 + i, x = - 1 - i

Solution steps

x^{3} = 2 x + 4

Move

4

to the left side

x^{3} - 4 = 2 x

Move

2 x

to the left side

x^{3} - 4 - 2 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} - 2 x - 4 = 0

Factor

x^{3} - 2 x - 4 : (x - 2) (x^{2} + 2 x + 2)

(x - 2) (x^{2} + 2 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x^{2} + 2 x + 2 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 2 = 0 : x = - 1 + i, x = - 1 - i

The solutions are

x = 2, x = - 1 + i, x = - 1 - i

x^{3} + 3 x^{2} - 4 x + 5 = 0

799675 = 524442 (1 + x)^{10}

6 x^{4} = 3072 x

(1 - x) (1 - x) (1 - x) + (1 - x) = 0

z^{7} = - 1 + 2 j

What are the solutions to the equation x^3=2x+4 ?
The solutions to the equation x^3=2x+4 are x=2,x=-1+i,x=-1-i
Find the zeros of x^3=2x+4
The zeros of x^3=2x+4 are x=2,x=-1+i,x=-1-i