What are the solutions to the equation x^4+2x^3-8x^2-18x-9=0 ?

The solutions to the equation x^4+2x^3-8x^2-18x-9=0 are x=-1,x=-3,x=3

Find the zeros of x^4+2x^3-8x^2-18x-9=0

The zeros of x^4+2x^3-8x^2-18x-9=0 are x=-1,x=-3,x=3

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x^{4} + 2 x^{3} - 8 x^{2} - 18 x - 9 = 0

x = - 1, x = - 3, x = 3

Solution steps

x^{4} + 2 x^{3} - 8 x^{2} - 18 x - 9 = 0

Factor

x^{4} + 2 x^{3} - 8 x^{2} - 18 x - 9 : (x + 1)^{2} (x + 3) (x - 3)

(x + 1)^{2} (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = - 3, x = 3

x^{3} + 91 x + 90 = 0

- x^{3} + 2 x^{2} + 4 x - 4 = 0

x^{3} - 10 x^{2} + 20 x = 26

3 x^{6} - 7 x^{2} = 0

3 x^{4} + 15 x^{2} - 17 = 0

What are the solutions to the equation x^4+2x^3-8x^2-18x-9=0 ?
The solutions to the equation x^4+2x^3-8x^2-18x-9=0 are x=-1,x=-3,x=3
Find the zeros of x^4+2x^3-8x^2-18x-9=0
The zeros of x^4+2x^3-8x^2-18x-9=0 are x=-1,x=-3,x=3