What are the solutions to the equation 3x^2-x^3-4=0 ?

The solutions to the equation 3x^2-x^3-4=0 are x=-1,x=2

Find the zeros of 3x^2-x^3-4=0

The zeros of 3x^2-x^3-4=0 are x=-1,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - x^{3} - 4 = 0

x = - 1, x = 2

Solution steps

3 x^{2} - x^{3} - 4 = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

- x^{3} + 3 x^{2} - 4 = 0

Factor

- x^{3} + 3 x^{2} - 4 : - (x + 1) (x - 2)^{2}

- (x + 1) (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = 2

- x^{6} - x^{5} + x^{4} + x^{3} = 0

79.97 x^{3} - 27.43 x - 52.14 = 0

x, x^{3} - 12 x + 16 = 0

2 x^{3} + 20 x^{2} + 50 x = 0

3^{10} = 3^{7} x^{3}

What are the solutions to the equation 3x^2-x^3-4=0 ?
The solutions to the equation 3x^2-x^3-4=0 are x=-1,x=2
Find the zeros of 3x^2-x^3-4=0
The zeros of 3x^2-x^3-4=0 are x=-1,x=2