What are the solutions to the equation z^3= 125/216 ?

The solutions to the equation z^3= 125/216 are z= 5/6 ,z=-5/12+5/(4sqrt(3))i,z=-5/12-5/(4sqrt(3))i

Find the zeros of z^3= 125/216

The zeros of z^3= 125/216 are z= 5/6 ,z=-5/12+5/(4sqrt(3))i,z=-5/12-5/(4sqrt(3))i

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z^{3} = \frac{125}{216}

z = \frac{5}{6}, z = - \frac{5}{12} + \frac{5}{4 3} i, z = - \frac{5}{12} - \frac{5}{4 3} i

Solution steps

z^{3} = \frac{125}{216}

For

x^{3} = f (a)

the solutions are

Simplify

z = \frac{5}{6}, z = - \frac{5}{12} + \frac{5}{4 3} i, z = - \frac{5}{12} - \frac{5}{4 3} i

4 x^{3} - 12 x^{2} - 16 x = 0

x^{5} + x + 1 = 1029

2 x^{4} + 6 x^{2} + 3 = 0

x^{3} + 2 x^{2} + 5 x + 10 = 0

e = (x + 1) (x^{2} - x + 1)

What are the solutions to the equation z^3= 125/216 ?
The solutions to the equation z^3= 125/216 are z= 5/6 ,z=-5/12+5/(4sqrt(3))i,z=-5/12-5/(4sqrt(3))i
Find the zeros of z^3= 125/216
The zeros of z^3= 125/216 are z= 5/6 ,z=-5/12+5/(4sqrt(3))i,z=-5/12-5/(4sqrt(3))i