What are the solutions to the equation 48=3r^4 ?

The solutions to the equation 48=3r^4 are r=2,r=-2,r=2i,r=-2i

Find the zeros of 48=3r^4

The zeros of 48=3r^4 are r=2,r=-2,r=2i,r=-2i

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48 = 3 r^{4}

r = 2, r = - 2, r = 2 i, r = - 2 i

Solution steps

48 = 3 r^{4}

Switch sides

3 r^{4} = 48

Divide both sides by

3

r^{4} = 16

Rewrite the equation with

u = r^{2}

and

u^{2} = r^{4}

u^{2} = 16

Solve

u^{2} = 16 : u = 16, u = - 16

u = 16, u = - 16

Substitute back

u = r^{2},

solve for

r

Solve

r^{2} = 16 : r = 2, r = - 2

Solve

r^{2} = - 16 : r = 2 i, r = - 2 i

The solutions are

r = 2, r = - 2, r = 2 i, r = - 2 i

x, 8 x^{3} + 4 y = 32

x^{3} + 8 = \frac{9 x ^{3}}{2}

x^{2} 5 x + 2 = - 4

(x) = \frac{x ^{3} + x - 1}{2}

x^{10} = 100

What are the solutions to the equation 48=3r^4 ?
The solutions to the equation 48=3r^4 are r=2,r=-2,r=2i,r=-2i
Find the zeros of 48=3r^4
The zeros of 48=3r^4 are r=2,r=-2,r=2i,r=-2i