What are the solutions to the equation (x+2)(x^2+6x+10)=0 ?

The solutions to the equation (x+2)(x^2+6x+10)=0 are x=-2,x=-3+i,x=-3-i

Find the zeros of (x+2)(x^2+6x+10)=0

The zeros of (x+2)(x^2+6x+10)=0 are x=-2,x=-3+i,x=-3-i

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(x + 2) (x^{2} + 6 x + 10) = 0

x = - 2, x = - 3 + i, x = - 3 - i

Solution steps

(x + 2) (x^{2} + 6 x + 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x^{2} + 6 x + 10 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x^{2} + 6 x + 10 = 0 : x = - 3 + i, x = - 3 - i

The solutions are

x = - 2, x = - 3 + i, x = - 3 - i

(2 x - 1)^{3} - 4 x (2 x - 3) = 5

a, a^{5} 4^{- 2} = 2

y^{3} = - 64

x^{3} = 243

y^{3} = - 27

What are the solutions to the equation (x+2)(x^2+6x+10)=0 ?
The solutions to the equation (x+2)(x^2+6x+10)=0 are x=-2,x=-3+i,x=-3-i
Find the zeros of (x+2)(x^2+6x+10)=0
The zeros of (x+2)(x^2+6x+10)=0 are x=-2,x=-3+i,x=-3-i