What are the solutions to the equation 125=m^3 ?

The solutions to the equation 125=m^3 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i

Find the zeros of 125=m^3

The zeros of 125=m^3 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i

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125 = m^{3}

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

Solution steps

125 = m^{3}

Switch sides

m^{3} = 125

For

x^{3} = f (a)

the solutions are

Simplify

m = 5, m = - \frac{5}{2} + \frac{5 3}{2} i, m = - \frac{5}{2} - \frac{5 3}{2} i

x^{3} + x^{2} + 6 x = 0

x^{4} + 3 x^{3} - 7 x^{2} + x + 2 = 0

p^{3} + 2 p - 27 = 2 p

x^{2} + x + 1 = x^{3} + x^{2} + 1

x^{4} + 4 x^{2} - 5 = 0

What are the solutions to the equation 125=m^3 ?
The solutions to the equation 125=m^3 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i
Find the zeros of 125=m^3
The zeros of 125=m^3 are m=5,m=-5/2+(5sqrt(3))/2 i,m=-5/2-(5sqrt(3))/2 i