What are the solutions to the equation x^4-x^3-5x^2+3x+6=0 ?

The solutions to the equation x^4-x^3-5x^2+3x+6=0 are x=-1,x=2,x=-sqrt(3),x=sqrt(3)

Find the zeros of x^4-x^3-5x^2+3x+6=0

The zeros of x^4-x^3-5x^2+3x+6=0 are x=-1,x=2,x=-sqrt(3),x=sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{4} - x^{3} - 5 x^{2} + 3 x + 6 = 0

x = - 1, x = 2, x = - 3, x = 3

Decimal Notation

x = - 1, x = 2, x = - 1.73205 \dots, x = 1.73205 \dots

Solution steps

x^{4} - x^{3} - 5 x^{2} + 3 x + 6 = 0

Factor

x^{4} - x^{3} - 5 x^{2} + 3 x + 6 : (x + 1) (x - 2) (x + 3) (x - 3)

(x + 1) (x - 2) (x + 3) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0 or x + 3 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

Solve

x + 3 = 0 : x = - 3

Solve

x - 3 = 0 : x = 3

The solutions are

x = - 1, x = 2, x = - 3, x = 3

x^{9} - x^{7} + x^{5} - x^{3} + x = 0

x^{4} - x^{3} - x - 1 = 0

3 x^{5} - 48 x^{3} = 0

0 = x^{4} - 4 x^{3} + 4 x^{2} - x

786000 = 247000 e^{17}

What are the solutions to the equation x^4-x^3-5x^2+3x+6=0 ?
The solutions to the equation x^4-x^3-5x^2+3x+6=0 are x=-1,x=2,x=-sqrt(3),x=sqrt(3)
Find the zeros of x^4-x^3-5x^2+3x+6=0
The zeros of x^4-x^3-5x^2+3x+6=0 are x=-1,x=2,x=-sqrt(3),x=sqrt(3)