What are the solutions to the equation -x^3+30x^2-279x+810=0 ?

The solutions to the equation -x^3+30x^2-279x+810=0 are x=6,x=9,x=15

Find the zeros of -x^3+30x^2-279x+810=0

The zeros of -x^3+30x^2-279x+810=0 are x=6,x=9,x=15

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- x^{3} + 30 x^{2} - 279 x + 810 = 0

x = 6, x = 9, x = 15

Solution steps

- x^{3} + 30 x^{2} - 279 x + 810 = 0

Factor

- x^{3} + 30 x^{2} - 279 x + 810 : - (x - 6) (x - 9) (x - 15)

- (x - 6) (x - 9) (x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x - 9 = 0 or x - 15 = 0

Solve

x - 6 = 0 : x = 6

Solve

x - 9 = 0 : x = 9

Solve

x - 15 = 0 : x = 15

The solutions are

x = 6, x = 9, x = 15

x^{4} - 4 x^{3} + 14 x^{2} - 4 x + 13 = 0

x^{4} - 2 x^{3} - 1 = 0

x^{4} + 7 x^{3} = 0

2 x^{5} - x^{4} - 2 x + 1 = 0

x^{3} - 11 x + 6 = 0

What are the solutions to the equation -x^3+30x^2-279x+810=0 ?
The solutions to the equation -x^3+30x^2-279x+810=0 are x=6,x=9,x=15
Find the zeros of -x^3+30x^2-279x+810=0
The zeros of -x^3+30x^2-279x+810=0 are x=6,x=9,x=15