What are the solutions to the equation 5x^2+15x-50=0 ?

The solutions to the equation 5x^2+15x-50=0 are x=2,x=-5

Find the zeros of 5x^2+15x-50=0

The zeros of 5x^2+15x-50=0 are x=2,x=-5

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5 x^{2} + 15 x - 50 = 0

x = 2, x = - 5

Solution steps

5 x^{2} + 15 x - 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 ( - 50 )}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 (- 50) = 35

x_{1, 2} = \frac{- 15 \pm 35}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 15 + 35}{2 \cdot 5}, x_{2} = \frac{- 15 - 35}{2 \cdot 5}

x = \frac{- 15 + 35}{2 \cdot 5} : 2

x = \frac{- 15 - 35}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

648 a + 1029 a^{4}

(3 x^{2})^{\frac{2}{3}}

3 (2 x - 1) - 2 (5 - x) = 3

- \frac{x}{2} + 20 \leq 4

(\frac{y}{5 x ^{- 2}})^{- 3}

What are the solutions to the equation 5x^2+15x-50=0 ?
The solutions to the equation 5x^2+15x-50=0 are x=2,x=-5
Find the zeros of 5x^2+15x-50=0
The zeros of 5x^2+15x-50=0 are x=2,x=-5