What are the solutions to the equation 3x^3-5x^2+2x=0 ?

The solutions to the equation 3x^3-5x^2+2x=0 are x=0,x= 2/3 ,x=1

Find the zeros of 3x^3-5x^2+2x=0

The zeros of 3x^3-5x^2+2x=0 are x=0,x= 2/3 ,x=1

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3 x^{3} - 5 x^{2} + 2 x = 0

x = 0, x = \frac{2}{3}, x = 1

Decimal Notation

x = 0, x = 0.66666 \dots, x = 1

Solution steps

3 x^{3} - 5 x^{2} + 2 x = 0

Factor

3 x^{3} - 5 x^{2} + 2 x : x (3 x - 2) (x - 1)

x (3 x - 2) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x - 2 = 0 or x - 1 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = \frac{2}{3}, x = 1

x, 0 = 324 x^{3} - 144 x y

z^{3} - 27 i = 0

3 x^{4} - 5 x^{3} + 2 x - 1 = 0

b^{4} - 2 = 1

x^{3} - 21 x^{2} = 0

What are the solutions to the equation 3x^3-5x^2+2x=0 ?
The solutions to the equation 3x^3-5x^2+2x=0 are x=0,x= 2/3 ,x=1
Find the zeros of 3x^3-5x^2+2x=0
The zeros of 3x^3-5x^2+2x=0 are x=0,x= 2/3 ,x=1