What are the solutions to the equation 2x^3-19x^2+64x-60=0 ?

The solutions to the equation 2x^3-19x^2+64x-60=0 are x= 3/2 ,x=4+2i,x=4-2i

Find the zeros of 2x^3-19x^2+64x-60=0

The zeros of 2x^3-19x^2+64x-60=0 are x= 3/2 ,x=4+2i,x=4-2i

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2 x^{3} - 19 x^{2} + 64 x - 60 = 0

x = \frac{3}{2}, x = 4 + 2 i, x = 4 - 2 i

Solution steps

2 x^{3} - 19 x^{2} + 64 x - 60 = 0

Factor

2 x^{3} - 19 x^{2} + 64 x - 60 : (2 x - 3) (x^{2} - 8 x + 20)

(2 x - 3) (x^{2} - 8 x + 20) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 3 = 0 or x^{2} - 8 x + 20 = 0

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

x^{2} - 8 x + 20 = 0 : x = 4 + 2 i, x = 4 - 2 i

The solutions are

x = \frac{3}{2}, x = 4 + 2 i, x = 4 - 2 i

y^{3} + 5 y^{2} - 9 y - 45 = 0

0 = x^{4} + 3

2 x^{3} - 8 x^{2} = 0

0 = x^{4} - 1

485 = 5 x^{3}

What are the solutions to the equation 2x^3-19x^2+64x-60=0 ?
The solutions to the equation 2x^3-19x^2+64x-60=0 are x= 3/2 ,x=4+2i,x=4-2i
Find the zeros of 2x^3-19x^2+64x-60=0
The zeros of 2x^3-19x^2+64x-60=0 are x= 3/2 ,x=4+2i,x=4-2i