What are the solutions to the equation r^3-5r^2+3r+9=0 ?

The solutions to the equation r^3-5r^2+3r+9=0 are r=-1,r=3

Find the zeros of r^3-5r^2+3r+9=0

The zeros of r^3-5r^2+3r+9=0 are r=-1,r=3

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r^{3} - 5 r^{2} + 3 r + 9 = 0

r = - 1, r = 3

Solution steps

r^{3} - 5 r^{2} + 3 r + 9 = 0

Factor

r^{3} - 5 r^{2} + 3 r + 9 : (r + 1) (r - 3)^{2}

(r + 1) (r - 3)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r + 1 = 0 or r - 3 = 0

Solve

r + 1 = 0 : r = - 1

Solve

r - 3 = 0 : r = 3

The solutions are

r = - 1, r = 3

x^{3} + 6 x^{2} - 4 x - 24 = 0

x^{3} + 2 x^{2} = 49 x + 98

m^{4} - 13 m^{2} - 48 = 0

x^{2} (x - 1) - 4 x^{2} + 8 x - 4 = 0

x^{3} + x = 3

What are the solutions to the equation r^3-5r^2+3r+9=0 ?
The solutions to the equation r^3-5r^2+3r+9=0 are r=-1,r=3
Find the zeros of r^3-5r^2+3r+9=0
The zeros of r^3-5r^2+3r+9=0 are r=-1,r=3