What are the solutions to the equation (2-x)*(2-x)*(4-x)=0 ?

The solutions to the equation (2-x)*(2-x)*(4-x)=0 are x=2,x=4

Find the zeros of (2-x)*(2-x)*(4-x)=0

The zeros of (2-x)*(2-x)*(4-x)=0 are x=2,x=4

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(2 - x) \cdot (2 - x) \cdot (4 - x) = 0

x = 2, x = 4

Solution steps

(2 - x) (2 - x) (4 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 - x = 0 or 2 - x = 0 or 4 - x = 0

Solve

2 - x = 0 : x = 2

Solve

2 - x = 0 : x = 2

Solve

4 - x = 0 : x = 4

The solutions are

x = 2, x = 4

x^{3} - 4 x - 4 = 0

0 = x^{3} + 64

20 x^{4} - 20 x^{3} = 0

x^{3} + 2 x^{2} - x = 2

x^{3} - 2 x^{2} - 3 = 0

What are the solutions to the equation (2-x)*(2-x)*(4-x)=0 ?
The solutions to the equation (2-x)*(2-x)*(4-x)=0 are x=2,x=4
Find the zeros of (2-x)*(2-x)*(4-x)=0
The zeros of (2-x)*(2-x)*(4-x)=0 are x=2,x=4