What is (x+2)/(x^2-5x-14)<= 0 ?

The solution to (x+2)/(x^2-5x-14)<= 0 is x<-2\lor-2<x<7

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(x+2)/(x^2-5x-14)<= 0

\frac{x + 2}{x ^{2} - 5 x - 14} \leq 0

x < - 2 or - 2 < x < 7

Interval Notation

(- \infty, - 2) \cup (- 2, 7)

Solution steps

\frac{x + 2}{x ^{2} - 5 x - 14} \leq 0

Factor

\frac{x + 2}{x ^{2} - 5 x - 14} : \frac{x + 2}{( x + 2 ) ( x - 7 )}

\frac{x + 2}{( x + 2 ) ( x - 7 )} \leq 0

Identify the intervals

x < - 2 or - 2 < x < 7

4 x^{2} + 8 x y + 3 y^{2}

20 + 45 - 5

6!

z^{2} + z - 30

- \frac{35}{2} (\frac{1}{10 0 ^{2}}) + \frac{35}{2}

What is (x+2)/(x^2-5x-14)<= 0 ?
The solution to (x+2)/(x^2-5x-14)<= 0 is x<-2\lor-2<x<7