What are the solutions to the equation (x^2-2)(5x+3)=0 ?

The solutions to the equation (x^2-2)(5x+3)=0 are x=-3/5 ,x=-sqrt(2),x=sqrt(2)

Find the zeros of (x^2-2)(5x+3)=0

The zeros of (x^2-2)(5x+3)=0 are x=-3/5 ,x=-sqrt(2),x=sqrt(2)

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(x^{2} - 2) (5 x + 3) = 0

x = - \frac{3}{5}, x = - 2, x = 2

Decimal Notation

x = - 0.6, x = - 1.41421 \dots, x = 1.41421 \dots

Solution steps

(x^{2} - 2) (5 x + 3) = 0

Factor

(x^{2} - 2) (5 x + 3) : (5 x + 3) (x + 2) (x - 2)

(5 x + 3) (x + 2) (x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 3 = 0 or x + 2 = 0 or x - 2 = 0

Solve

5 x + 3 = 0 : x = - \frac{3}{5}

Solve

x + 2 = 0 : x = - 2

Solve

x - 2 = 0 : x = 2

The solutions are

x = - \frac{3}{5}, x = - 2, x = 2

12 x^{3} + 12 x^{2} + 12 x = 0

x^{3} - 7 x^{2} + 8 x - 2 = 0

0 = x^{3} - 2 x

4 x^{3} - 3 x - 2 = 0

x^{3} - 7 x^{2} + 9 x + 5 = 0

What are the solutions to the equation (x^2-2)(5x+3)=0 ?
The solutions to the equation (x^2-2)(5x+3)=0 are x=-3/5 ,x=-sqrt(2),x=sqrt(2)
Find the zeros of (x^2-2)(5x+3)=0
The zeros of (x^2-2)(5x+3)=0 are x=-3/5 ,x=-sqrt(2),x=sqrt(2)