What are the solutions to the equation x(x+4)(4x-3)=0 ?

The solutions to the equation x(x+4)(4x-3)=0 are x=0,x=-4,x= 3/4

Find the zeros of x(x+4)(4x-3)=0

The zeros of x(x+4)(4x-3)=0 are x=0,x=-4,x= 3/4

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x (x + 4) (4 x - 3) = 0

x = 0, x = - 4, x = \frac{3}{4}

Decimal Notation

x = 0, x = - 4, x = 0.75

Solution steps

x (x + 4) (4 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 4 = 0 or 4 x - 3 = 0

Solve

x + 4 = 0 : x = - 4

Solve

4 x - 3 = 0 : x = \frac{3}{4}

The solutions are

x = 0, x = - 4, x = \frac{3}{4}

16 x^{4} + 25 = 41 x^{2}

s^{4} + 5 s^{3} + 8 s^{2} + 3.93 s - 14 = 0

m^{3} - 4 m^{2} + 5 m = 0

3 = 0.03 t^{3} + 0.05 t^{2}

2418 = 2330 \cdot (1 + r)^{15}

What are the solutions to the equation x(x+4)(4x-3)=0 ?
The solutions to the equation x(x+4)(4x-3)=0 are x=0,x=-4,x= 3/4
Find the zeros of x(x+4)(4x-3)=0
The zeros of x(x+4)(4x-3)=0 are x=0,x=-4,x= 3/4