What are the solutions to the equation -4x^3+24x^2+x-6=0 ?

The solutions to the equation -4x^3+24x^2+x-6=0 are x=6,x=-1/2 ,x= 1/2

Find the zeros of -4x^3+24x^2+x-6=0

The zeros of -4x^3+24x^2+x-6=0 are x=6,x=-1/2 ,x= 1/2

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- 4 x^{3} + 24 x^{2} + x - 6 = 0

x = 6, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 6, x = - 0.5, x = 0.5

Solution steps

- 4 x^{3} + 24 x^{2} + x - 6 = 0

Factor

- 4 x^{3} + 24 x^{2} + x - 6 : - (x - 6) (2 x + 1) (2 x - 1)

- (x - 6) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x - 6 = 0 : x = 6

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 6, x = - \frac{1}{2}, x = \frac{1}{2}

- x^{3} + 7 x - 2 = x^{2} + 3 x - 3

x^{9} + 27 x^{6} = 0

x^{3} - 5 x + 6 = 0

(k^{2} + 4)^{2} = 0

25 x^{4} - 689 x^{2} + 1600 = 0

What are the solutions to the equation -4x^3+24x^2+x-6=0 ?
The solutions to the equation -4x^3+24x^2+x-6=0 are x=6,x=-1/2 ,x= 1/2
Find the zeros of -4x^3+24x^2+x-6=0
The zeros of -4x^3+24x^2+x-6=0 are x=6,x=-1/2 ,x= 1/2