What are the solutions to the equation x^2(5x-7)(3x+2)=0 ?

The solutions to the equation x^2(5x-7)(3x+2)=0 are x=0,x= 7/5 ,x=-2/3

Find the zeros of x^2(5x-7)(3x+2)=0

The zeros of x^2(5x-7)(3x+2)=0 are x=0,x= 7/5 ,x=-2/3

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x^{2} (5 x - 7) (3 x + 2) = 0

x = 0, x = \frac{7}{5}, x = - \frac{2}{3}

Decimal Notation

x = 0, x = 1.4, x = - 0.66666 \dots

Solution steps

x^{2} (5 x - 7) (3 x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 5 x - 7 = 0 or 3 x + 2 = 0

Solve

5 x - 7 = 0 : x = \frac{7}{5}

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

The solutions are

x = 0, x = \frac{7}{5}, x = - \frac{2}{3}

3 x^{3} + 4 x^{2} = 15 x

x^{3} - 3 x^{2} - 9 x + 21 = 0

t^{3} = 30

x^{4} - 2 x^{3} + 5 x - 1 = 0

w, w^{3} = - 2 - 23 i

What are the solutions to the equation x^2(5x-7)(3x+2)=0 ?
The solutions to the equation x^2(5x-7)(3x+2)=0 are x=0,x= 7/5 ,x=-2/3
Find the zeros of x^2(5x-7)(3x+2)=0
The zeros of x^2(5x-7)(3x+2)=0 are x=0,x= 7/5 ,x=-2/3