What are the solutions to the equation -3(9x^2-4)(x^2-15)=0 ?

The solutions to the equation -3(9x^2-4)(x^2-15)=0 are x=-2/3 ,x= 2/3 ,x=-sqrt(15),x=sqrt(15)

Find the zeros of -3(9x^2-4)(x^2-15)=0

The zeros of -3(9x^2-4)(x^2-15)=0 are x=-2/3 ,x= 2/3 ,x=-sqrt(15),x=sqrt(15)

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- 3 (9 x^{2} - 4) (x^{2} - 15) = 0

x = - \frac{2}{3}, x = \frac{2}{3}, x = - 15, x = 15

Decimal

x = - 0.66666 \dots, x = 0.66666 \dots, x = - 3.87298 \dots, x = 3.87298 \dots

Solution steps

- 3 (9 x^{2} - 4) (x^{2} - 15) = 0

Factor

- 3 (9 x^{2} - 4) (x^{2} - 15) : - 3 (3 x + 2) (3 x - 2) (x + 15) (x - 15)

- 3 (3 x + 2) (3 x - 2) (x + 15) (x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or 3 x - 2 = 0 or x + 15 = 0 or x - 15 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x + 15 = 0 : x = - 15

Solve

x - 15 = 0 : x = 15

The solutions are

x = - \frac{2}{3}, x = \frac{2}{3}, x = - 15, x = 15

u^{5} = 243

x^{3} + 5 x^{2} - 11 x - 55 = 0

x^{3} + 21 x^{2} + 2520 x + 2500 = 0

(2 x - 3)^{5} = 243

t^{3} = 64

What are the solutions to the equation -3(9x^2-4)(x^2-15)=0 ?
The solutions to the equation -3(9x^2-4)(x^2-15)=0 are x=-2/3 ,x= 2/3 ,x=-sqrt(15),x=sqrt(15)
Find the zeros of -3(9x^2-4)(x^2-15)=0
The zeros of -3(9x^2-4)(x^2-15)=0 are x=-2/3 ,x= 2/3 ,x=-sqrt(15),x=sqrt(15)