What are the solutions to the equation (r^2+2r+10)3r(r+1)2=0 ?

The solutions to the equation (r^2+2r+10)3r(r+1)2=0 are r=-1+3i,r=-1-3i,r=0,r=-1

Find the zeros of (r^2+2r+10)3r(r+1)2=0

The zeros of (r^2+2r+10)3r(r+1)2=0 are r=-1+3i,r=-1-3i,r=0,r=-1

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(r^{2} + 2 r + 10) 3 r (r + 1) 2 = 0

r = - 1 + 3 i, r = - 1 - 3 i, r = 0, r = - 1

Solution steps

(r^{2} + 2 r + 10) \cdot 3 r (r + 1) \cdot 2 = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r^{2} + 2 r + 10 = 0 or r = 0 or r + 1 = 0

Solve

r^{2} + 2 r + 10 = 0 : r = - 1 + 3 i, r = - 1 - 3 i

Solve

r + 1 = 0 : r = - 1

The solutions are

r = - 1 + 3 i, r = - 1 - 3 i, r = 0, r = - 1

2 x^{5} - x^{3} + 2 x^{2} - 1 = 0

5 x^{3} - 5 x = 0

k^{4} - 1 = 0

z^{4} + 4 i z^{2} + 8 = 0

x^{100} = 0

What are the solutions to the equation (r^2+2r+10)3r(r+1)2=0 ?
The solutions to the equation (r^2+2r+10)3r(r+1)2=0 are r=-1+3i,r=-1-3i,r=0,r=-1
Find the zeros of (r^2+2r+10)3r(r+1)2=0
The zeros of (r^2+2r+10)3r(r+1)2=0 are r=-1+3i,r=-1-3i,r=0,r=-1