What are the solutions to the equation 3(x+7)^3=648 ?

The solutions to the equation 3(x+7)^3=648 are x=-1,x=-10+3sqrt(3)i,x=-10-3sqrt(3)i

Find the zeros of 3(x+7)^3=648

The zeros of 3(x+7)^3=648 are x=-1,x=-10+3sqrt(3)i,x=-10-3sqrt(3)i

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3 (x + 7)^{3} = 648

x = - 1, x = - 10 + 33 i, x = - 10 - 33 i

Solution steps

3 (x + 7)^{3} = 648

Divide both sides by

3

(x + 7)^{3} = 216

For

g^{3} (x) = f (a)

the solutions are

Solve

The solutions are

x = - 1, x = - 10 + 33 i, x = - 10 - 33 i

4 x^{3} - 20 x^{2} = 0

0 = x^{4} - 4 x^{3} + 7

x^{3} - 9 x - 5 = 0

x^{3} - 7 x = 0

2 x^{3} - 5 x^{2} + 2 x - 5 = 0

What are the solutions to the equation 3(x+7)^3=648 ?
The solutions to the equation 3(x+7)^3=648 are x=-1,x=-10+3sqrt(3)i,x=-10-3sqrt(3)i
Find the zeros of 3(x+7)^3=648
The zeros of 3(x+7)^3=648 are x=-1,x=-10+3sqrt(3)i,x=-10-3sqrt(3)i