What are the solutions to the equation x^3-9x-4=0 ?

The solutions to the equation x^3-9x-4=0 are x\approx-0.45490…,x\approx-2.74656…,x\approx 3.20147…

Find the zeros of x^3-9x-4=0

The zeros of x^3-9x-4=0 are x\approx-0.45490…,x\approx-2.74656…,x\approx 3.20147…

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x^{3} - 9 x - 4 = 0

x \approx - 0.45490 \dots, x \approx - 2.74656 \dots, x \approx 3.20147 \dots

Solution steps

x^{3} - 9 x - 4 = 0

Find one solution for

x^{3} - 9 x - 4 = 0

using Newton-Raphson:

x \approx - 0.45490 \dots

Apply long division:

\frac{x ^{3} - 9 x - 4}{x + 0.45490 \dots} = x^{2} - 0.45490 \dots x - 8.79306 \dots

x^{2} - 0.45490 \dots x - 8.79306 \dots \approx 0

Find one solution for

x^{2} - 0.45490 \dots x - 8.79306 \dots = 0

using Newton-Raphson:

x \approx - 2.74656 \dots

Apply long division:

\frac{x ^{2} - 0.45490 \dots x - 8.79306 \dots}{x + 2.74656 \dots} = x - 3.20147 \dots

x - 3.20147 \dots \approx 0

x \approx 3.20147 \dots

The solutions are

x \approx - 0.45490 \dots, x \approx - 2.74656 \dots, x \approx 3.20147 \dots

x^{3} + x^{2} + 25 x + 25 = 0

0 = x^{3} - x^{2}

[- 4 (k) (k)]^{2} - 4 (1) (k^{4}) = 0

45 = x^{3}

x^{3} - 3 x + 4 = 5.9

What are the solutions to the equation x^3-9x-4=0 ?
The solutions to the equation x^3-9x-4=0 are x\approx-0.45490…,x\approx-2.74656…,x\approx 3.20147…
Find the zeros of x^3-9x-4=0
The zeros of x^3-9x-4=0 are x\approx-0.45490…,x\approx-2.74656…,x\approx 3.20147…