What are the solutions to the equation x^3-9x-1=0 ?

The solutions to the equation x^3-9x-1=0 are x\approx-0.11126…,x\approx-2.94282…,x\approx 3.05408…

Find the zeros of x^3-9x-1=0

The zeros of x^3-9x-1=0 are x\approx-0.11126…,x\approx-2.94282…,x\approx 3.05408…

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x^{3} - 9 x - 1 = 0

x \approx - 0.11126 \dots, x \approx - 2.94282 \dots, x \approx 3.05408 \dots

Solution steps

x^{3} - 9 x - 1 = 0

Find one solution for

x^{3} - 9 x - 1 = 0

using Newton-Raphson:

x \approx - 0.11126 \dots

Apply long division:

\frac{x ^{3} - 9 x - 1}{x + 0.11126 \dots} = x^{2} - 0.11126 \dots x - 8.98762 \dots

x^{2} - 0.11126 \dots x - 8.98762 \dots \approx 0

Find one solution for

x^{2} - 0.11126 \dots x - 8.98762 \dots = 0

using Newton-Raphson:

x \approx - 2.94282 \dots

Apply long division:

\frac{x ^{2} - 0.11126 \dots x - 8.98762 \dots}{x + 2.94282 \dots} = x - 3.05408 \dots

x - 3.05408 \dots \approx 0

x \approx 3.05408 \dots

The solutions are

x \approx - 0.11126 \dots, x \approx - 2.94282 \dots, x \approx 3.05408 \dots

x^{(3)} + 3 x^{(2)} - 4 x - 12 = 0

4 x^{4} - 5 x^{2} - 9 = 0

x^{2} (x + 5) = 0

x^{3} + 4 x^{2} - 5 x + 1 = 0

\frac{( x ^{3} - 2 )}{( - 1 )} = - 25

What are the solutions to the equation x^3-9x-1=0 ?
The solutions to the equation x^3-9x-1=0 are x\approx-0.11126…,x\approx-2.94282…,x\approx 3.05408…
Find the zeros of x^3-9x-1=0
The zeros of x^3-9x-1=0 are x\approx-0.11126…,x\approx-2.94282…,x\approx 3.05408…