What are the solutions to the equation 25c+10c^2=0 ?

The solutions to the equation 25c+10c^2=0 are c=0,c=-5/2

Find the zeros of 25c+10c^2=0

The zeros of 25c+10c^2=0 are c=0,c=-5/2

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25 c + 10 c^{2} = 0

c = 0, c = - \frac{5}{2}

Decimal Notation

c = 0, c = - 2.5

Solution steps

25 c + 10 c^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

10 c^{2} + 25 c = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 10 \cdot 0}{2 \cdot 10}

2 5^{2} - 4 \cdot 10 \cdot 0 = 25

c_{1, 2} = \frac{- 25 \pm 25}{2 \cdot 10}

Separate the solutions

c_{1} = \frac{- 25 + 25}{2 \cdot 10}, c_{2} = \frac{- 25 - 25}{2 \cdot 10}

c = \frac{- 25 + 25}{2 \cdot 10} : 0

c = \frac{- 25 - 25}{2 \cdot 10} : - \frac{5}{2}

The solutions to the quadratic equation are:

c = 0, c = - \frac{5}{2}

1.06 x - 2 \leq 0.544

5 x - 40 > 2 (2 + 8 x)

10 + 10

9 x^{4} + 4 x^{2}

(x^{2} - \frac{1}{x ^{2}})^{- 3}

What are the solutions to the equation 25c+10c^2=0 ?
The solutions to the equation 25c+10c^2=0 are c=0,c=-5/2
Find the zeros of 25c+10c^2=0
The zeros of 25c+10c^2=0 are c=0,c=-5/2