What are the solutions to the equation (x^2-5)(x-2)=0 ?

The solutions to the equation (x^2-5)(x-2)=0 are x=2,x=-sqrt(5),x=sqrt(5)

Find the zeros of (x^2-5)(x-2)=0

The zeros of (x^2-5)(x-2)=0 are x=2,x=-sqrt(5),x=sqrt(5)

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(x^{2} - 5) (x - 2) = 0

x = 2, x = - 5, x = 5

Decimal Notation

x = 2, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

(x^{2} - 5) (x - 2) = 0

Factor

(x^{2} - 5) (x - 2) : (x - 2) (x + 5) (x - 5)

(x - 2) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x + 5 = 0 or x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = 2, x = - 5, x = 5

12 x^{3} + 27 x^{2} - 30 x = 0

(1 - x^{2})^{2} = 0

4 x^{3} + 6 x = 0

x^{3} = - 343

2 x^{3} + 6 x^{2} + 1 = 0

What are the solutions to the equation (x^2-5)(x-2)=0 ?
The solutions to the equation (x^2-5)(x-2)=0 are x=2,x=-sqrt(5),x=sqrt(5)
Find the zeros of (x^2-5)(x-2)=0
The zeros of (x^2-5)(x-2)=0 are x=2,x=-sqrt(5),x=sqrt(5)