What are the solutions to the equation 6x^3-47x^2+36x-7=0 ?

The solutions to the equation 6x^3-47x^2+36x-7=0 are x=7,x= 1/3 ,x= 1/2

Find the zeros of 6x^3-47x^2+36x-7=0

The zeros of 6x^3-47x^2+36x-7=0 are x=7,x= 1/3 ,x= 1/2

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6 x^{3} - 47 x^{2} + 36 x - 7 = 0

x = 7, x = \frac{1}{3}, x = \frac{1}{2}

Decimal Notation

x = 7, x = 0.33333 \dots, x = 0.5

Solution steps

6 x^{3} - 47 x^{2} + 36 x - 7 = 0

Factor

6 x^{3} - 47 x^{2} + 36 x - 7 : (x - 7) (3 x - 1) (2 x - 1)

(x - 7) (3 x - 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 7 = 0 or 3 x - 1 = 0 or 2 x - 1 = 0

Solve

x - 7 = 0 : x = 7

Solve

3 x - 1 = 0 : x = \frac{1}{3}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 7, x = \frac{1}{3}, x = \frac{1}{2}

x^{3} - 5 x^{2} + 4 x + 6 = 0

3 b = 9 (b^{3} + 3)

x, x^{4} + 4 y^{2} = z^{2}

y^{(10)} = 0

27 x^{3} + 27 x^{2} + 9 x = - 1

What are the solutions to the equation 6x^3-47x^2+36x-7=0 ?
The solutions to the equation 6x^3-47x^2+36x-7=0 are x=7,x= 1/3 ,x= 1/2
Find the zeros of 6x^3-47x^2+36x-7=0
The zeros of 6x^3-47x^2+36x-7=0 are x=7,x= 1/3 ,x= 1/2