What are the solutions to the equation 8x^3-52x^2+78x-27=0 ?

The solutions to the equation 8x^3-52x^2+78x-27=0 are x= 1/2 ,x= 3/2 ,x= 9/2

Find the zeros of 8x^3-52x^2+78x-27=0

The zeros of 8x^3-52x^2+78x-27=0 are x= 1/2 ,x= 3/2 ,x= 9/2

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8 x^{3} - 52 x^{2} + 78 x - 27 = 0

x = \frac{1}{2}, x = \frac{3}{2}, x = \frac{9}{2}

Decimal Notation

x = 0.5, x = 1.5, x = 4.5

Solution steps

8 x^{3} - 52 x^{2} + 78 x - 27 = 0

Factor

8 x^{3} - 52 x^{2} + 78 x - 27 : (2 x - 1) (2 x - 3) (2 x - 9)

(2 x - 1) (2 x - 3) (2 x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or 2 x - 3 = 0 or 2 x - 9 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

Solve

2 x - 9 = 0 : x = \frac{9}{2}

The solutions are

x = \frac{1}{2}, x = \frac{3}{2}, x = \frac{9}{2}

3 x^{3} + 48 = 0

\frac{1}{6} a^{4} = 1, a^{2} = 1

4 x^{3} + 8 x = 0

- 12 x^{5} - 6 x^{3} = - 10

x^{3} + 4 x^{2} - 44 x - 96 = 0

What are the solutions to the equation 8x^3-52x^2+78x-27=0 ?
The solutions to the equation 8x^3-52x^2+78x-27=0 are x= 1/2 ,x= 3/2 ,x= 9/2
Find the zeros of 8x^3-52x^2+78x-27=0
The zeros of 8x^3-52x^2+78x-27=0 are x= 1/2 ,x= 3/2 ,x= 9/2