What is (x^2-1/(x^2))^{-3} ?

The solution to (x^2-1/(x^2))^{-3} is (x^6)/((x^4-1)^3)

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simplify (x^2-1/(x^2))^{-3}

simplify

(x^{2} - \frac{1}{x ^{2}})^{- 3}

\frac{x ^{6}}{( x ^{4} - 1 ) ^{3}}

Solution steps

(x^{2} - \frac{1}{x ^{2}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(x^{2} - \frac{1}{x ^{2}})^{- 3} = \frac{1}{( x ^{2} - \frac{1}{x ^{2}} ) ^{3}}

= \frac{1}{( x ^{2} - \frac{1}{x ^{2}} ) ^{3}}

Simplify

(x^{2} - \frac{1}{x ^{2}})^{3} : \frac{( x ^{4} - 1 ) ^{3}}{x ^{6}}

= \frac{1}{\frac{( x ^{4} - 1 ) ^{3}}{x ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{6}}{( x ^{4} - 1 ) ^{3}}

\frac{1}{7} v + \frac{4}{7} w + 4 + \frac{5}{7} v

9 p - 9 < 4 p - 2

(4 x - 2)^{2} - (x - 2)^{2} = 9

∣ 9 - 2 x ∣ = 3

(x - 1) (x + 1) + (x - 1) (x + 2)

What is (x^2-1/(x^2))^{-3} ?
The solution to (x^2-1/(x^2))^{-3} is (x^6)/((x^4-1)^3)