What are the solutions to the equation 3x^3+6x^2=9x ?

The solutions to the equation 3x^3+6x^2=9x are x=0,x=1,x=-3

Find the zeros of 3x^3+6x^2=9x

The zeros of 3x^3+6x^2=9x are x=0,x=1,x=-3

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3 x^{3} + 6 x^{2} = 9 x

x = 0, x = 1, x = - 3

Solution steps

3 x^{3} + 6 x^{2} = 9 x

Move

9 x

to the left side

3 x^{3} + 6 x^{2} - 9 x = 0

Factor

3 x^{3} + 6 x^{2} - 9 x : 3 x (x - 1) (x + 3)

3 x (x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 3 = 0 : x = - 3

The solutions are

x = 0, x = 1, x = - 3

5^{2} = 5 x^{5}

x, y + 1 = x^{3}

w w^{2} - 6 w - 7 = 0

x^{5} - 6 x + 3 = 0

x^{3} + 6 x^{2} = - x^{2} + 5 x + 2

What are the solutions to the equation 3x^3+6x^2=9x ?
The solutions to the equation 3x^3+6x^2=9x are x=0,x=1,x=-3
Find the zeros of 3x^3+6x^2=9x
The zeros of 3x^3+6x^2=9x are x=0,x=1,x=-3