What are the solutions to the equation -a^3+24a^2-180a+432=0 ?

The solutions to the equation -a^3+24a^2-180a+432=0 are a=6,a=12

Find the zeros of -a^3+24a^2-180a+432=0

The zeros of -a^3+24a^2-180a+432=0 are a=6,a=12

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- a^{3} + 24 a^{2} - 180 a + 432 = 0

a = 6, a = 12

Solution steps

- a^{3} + 24 a^{2} - 180 a + 432 = 0

Factor

- a^{3} + 24 a^{2} - 180 a + 432 : - (a - 6)^{2} (a - 12)

- (a - 6)^{2} (a - 12) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a - 6 = 0 or a - 12 = 0

Solve

a - 6 = 0 : a = 6

Solve

a - 12 = 0 : a = 12

The solutions are

a = 6, a = 12

x^{4} = 6 x^{2}

(9 x - 4) x^{7} = 7 x (9 x - 4)

x^{9} = 1 0^{63}

y^{8} + 16 = 17 y^{4}

x^{7} = x^{5}

What are the solutions to the equation -a^3+24a^2-180a+432=0 ?
The solutions to the equation -a^3+24a^2-180a+432=0 are a=6,a=12
Find the zeros of -a^3+24a^2-180a+432=0
The zeros of -a^3+24a^2-180a+432=0 are a=6,a=12