What are the solutions to the equation x(x^2-2x-3)=0 ?

The solutions to the equation x(x^2-2x-3)=0 are x=0,x=-1,x=3

Find the zeros of x(x^2-2x-3)=0

The zeros of x(x^2-2x-3)=0 are x=0,x=-1,x=3

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x (x^{2} - 2 x - 3) = 0

x = 0, x = - 1, x = 3

Solution steps

x (x^{2} - 2 x - 3) = 0

Factor

x (x^{2} - 2 x - 3) : x (x + 1) (x - 3)

x (x + 1) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 3 = 0 : x = 3

The solutions are

x = 0, x = - 1, x = 3

(1 \cdot x)^{60} = 1.1051

3 x^{3} - 4 x^{2} - 12 x + 16 = 0

20124 = e^{3}

2 x - 6 + 4 x^{3} = 0

x^{4} - 170 x^{2} + 169 = 0

What are the solutions to the equation x(x^2-2x-3)=0 ?
The solutions to the equation x(x^2-2x-3)=0 are x=0,x=-1,x=3
Find the zeros of x(x^2-2x-3)=0
The zeros of x(x^2-2x-3)=0 are x=0,x=-1,x=3