What are the solutions to the equation 27/8 =x^3 ?

The solutions to the equation 27/8 =x^3 are x= 3/2 ,x=-3/4+(3sqrt(3))/4 i,x=-3/4-(3sqrt(3))/4 i

Find the zeros of 27/8 =x^3

The zeros of 27/8 =x^3 are x= 3/2 ,x=-3/4+(3sqrt(3))/4 i,x=-3/4-(3sqrt(3))/4 i

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\frac{27}{8} = x^{3}

x = \frac{3}{2}, x = - \frac{3}{4} + \frac{3 3}{4} i, x = - \frac{3}{4} - \frac{3 3}{4} i

Solution steps

\frac{27}{8} = x^{3}

Switch sides

x^{3} = \frac{27}{8}

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{3}{2}, x = - \frac{3}{4} + \frac{3 3}{4} i, x = - \frac{3}{4} - \frac{3 3}{4} i

x^{4} - 2 x^{3} - 4 x^{2} + 5 x - 6 = 0

18 x^{2} - 9 x^{4} = 0

0 = 2 x^{4} + 6 x^{2} + 8

y (2 - y) (4 - y) = 0

30 = 0.05625 (x - 22)^{4} - 16.9

What are the solutions to the equation 27/8 =x^3 ?
The solutions to the equation 27/8 =x^3 are x= 3/2 ,x=-3/4+(3sqrt(3))/4 i,x=-3/4-(3sqrt(3))/4 i
Find the zeros of 27/8 =x^3
The zeros of 27/8 =x^3 are x= 3/2 ,x=-3/4+(3sqrt(3))/4 i,x=-3/4-(3sqrt(3))/4 i