What are the solutions to the equation x^3+3x^2-6x=0 ?

The solutions to the equation x^3+3x^2-6x=0 are x=0,x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2

Find the zeros of x^3+3x^2-6x=0

The zeros of x^3+3x^2-6x=0 are x=0,x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2

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x^{3} + 3 x^{2} - 6 x = 0

x = 0, x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

Decimal Notation

x = 0, x = 1.37228 \dots, x = - 4.37228 \dots

Solution steps

x^{3} + 3 x^{2} - 6 x = 0

Factor

x^{3} + 3 x^{2} - 6 x : x (x^{2} + 3 x - 6)

x (x^{2} + 3 x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x^{2} + 3 x - 6 = 0

Solve

x^{2} + 3 x - 6 = 0 : x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

The solutions are

x = 0, x = \frac{- 3 + 33}{2}, x = \frac{- 3 - 33}{2}

x (6 - 2 x)^{2} = 0

y, x = 1 - ((1 - y)^{12})

(x^{2} + 6 x) (x + 3)^{2} = 400

x^{4} - 14 x^{2} + 48 = 0

x^{3} + 6 x^{2} + 11 x - 6 = 0

What are the solutions to the equation x^3+3x^2-6x=0 ?
The solutions to the equation x^3+3x^2-6x=0 are x=0,x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2
Find the zeros of x^3+3x^2-6x=0
The zeros of x^3+3x^2-6x=0 are x=0,x=(-3+sqrt(33))/2 ,x=(-3-sqrt(33))/2