What are the solutions to the equation 3x^2+3x+7=0 ?

The solutions to the equation 3x^2+3x+7=0 are x=-1/2+i(5sqrt(3))/6 ,x=-1/2-i(5sqrt(3))/6

Find the zeros of 3x^2+3x+7=0

The zeros of 3x^2+3x+7=0 are x=-1/2+i(5sqrt(3))/6 ,x=-1/2-i(5sqrt(3))/6

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3 x^{2} + 3 x + 7 = 0

x = - \frac{1}{2} + i \frac{5 3}{6}, x = - \frac{1}{2} - i \frac{5 3}{6}

Solution steps

3 x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

3^{2} - 4 \cdot 3 \cdot 7 : 53 i

x_{1, 2} = \frac{- 3 \pm 5 3 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 3 + 5 3 i}{2 \cdot 3}, x_{2} = \frac{- 3 - 5 3 i}{2 \cdot 3}

x = \frac{- 3 + 5 3 i}{2 \cdot 3} : - \frac{1}{2} + i \frac{5 3}{6}

x = \frac{- 3 - 5 3 i}{2 \cdot 3} : - \frac{1}{2} - i \frac{5 3}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{5 3}{6}, x = - \frac{1}{2} - i \frac{5 3}{6}

∣ 6 x - 6 ∣ < 24

\frac{( x - 66.5 )}{2.8} \leq 1

\frac{1}{2} + \frac{2}{5}

2 x^{2} - 7 x + 5

5 x^{4} - 46 x^{3} + 84 x^{2} - 50 x + 7

What are the solutions to the equation 3x^2+3x+7=0 ?
The solutions to the equation 3x^2+3x+7=0 are x=-1/2+i(5sqrt(3))/6 ,x=-1/2-i(5sqrt(3))/6
Find the zeros of 3x^2+3x+7=0
The zeros of 3x^2+3x+7=0 are x=-1/2+i(5sqrt(3))/6 ,x=-1/2-i(5sqrt(3))/6