What are the solutions to the equation (z^2)/6-(3z)/2-60=0 ?

The solutions to the equation (z^2)/6-(3z)/2-60=0 are z=24,z=-15

Find the zeros of (z^2)/6-(3z)/2-60=0

The zeros of (z^2)/6-(3z)/2-60=0 are z=24,z=-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{z ^{2}}{6} - \frac{3 z}{2} - 60 = 0

z = 24, z = - 15

Solution steps

\frac{z ^{2}}{6} - \frac{3 z}{2} - 60 = 0

Find Least Common Multiplier of

6, 2 : 6

Multiply by LCM=

6

\frac{z ^{2}}{6} \cdot 6 - \frac{3 z}{2} \cdot 6 - 60 \cdot 6 = 0 \cdot 6

Simplify

z^{2} - 9 z - 360 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( - 360 )}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot (- 360) = 39

z_{1, 2} = \frac{- ( - 9 ) \pm 39}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 9 ) + 39}{2 \cdot 1}, z_{2} = \frac{- ( - 9 ) - 39}{2 \cdot 1}

z = \frac{- ( - 9 ) + 39}{2 \cdot 1} : 24

z = \frac{- ( - 9 ) - 39}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

z = 24, z = - 15

10 x = 4

\frac{6 3}{6}

(x + 8)^{2} - 7 = 0

1^{2} + 3

a q + a u + q y + u y

What are the solutions to the equation (z^2)/6-(3z)/2-60=0 ?
The solutions to the equation (z^2)/6-(3z)/2-60=0 are z=24,z=-15
Find the zeros of (z^2)/6-(3z)/2-60=0
The zeros of (z^2)/6-(3z)/2-60=0 are z=24,z=-15