What are the solutions to the equation -x^3-5x^2+25x+125=0 ?

The solutions to the equation -x^3-5x^2+25x+125=0 are x=-5,x=5

Find the zeros of -x^3-5x^2+25x+125=0

The zeros of -x^3-5x^2+25x+125=0 are x=-5,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{3} - 5 x^{2} + 25 x + 125 = 0

x = - 5, x = 5

Solution steps

- x^{3} - 5 x^{2} + 25 x + 125 = 0

Factor

- x^{3} - 5 x^{2} + 25 x + 125 : - (x + 5)^{2} (x - 5)

- (x + 5)^{2} (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 5 = 0 or x - 5 = 0

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 5, x = 5

2 x^{3} - 2 x^{2} - 1 = 0

x^{4} + 149 x^{2} + 4900 = 0

\frac{1}{2 a} = n^{3}

x^{4} + x^{3} - x - 1 = 0

9 y^{3} + 8 = 4 y + 18 y^{2}

What are the solutions to the equation -x^3-5x^2+25x+125=0 ?
The solutions to the equation -x^3-5x^2+25x+125=0 are x=-5,x=5
Find the zeros of -x^3-5x^2+25x+125=0
The zeros of -x^3-5x^2+25x+125=0 are x=-5,x=5