What are the solutions to the equation (x^2-3x)(2x+3)(x-1)=0 ?

The solutions to the equation (x^2-3x)(2x+3)(x-1)=0 are x=0,x=3,x=1,x=-3/2

Find the zeros of (x^2-3x)(2x+3)(x-1)=0

The zeros of (x^2-3x)(2x+3)(x-1)=0 are x=0,x=3,x=1,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^{2} - 3 x) (2 x + 3) (x - 1) = 0

x = 0, x = 3, x = 1, x = - \frac{3}{2}

Decimal Notation

x = 0, x = 3, x = 1, x = - 1.5

Solution steps

(x^{2} - 3 x) (2 x + 3) (x - 1) = 0

Factor

(x^{2} - 3 x) (2 x + 3) (x - 1) : x (x - 3) (x - 1) (2 x + 3)

x (x - 3) (x - 1) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0 or x - 1 = 0 or 2 x + 3 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 1 = 0 : x = 1

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions are

x = 0, x = 3, x = 1, x = - \frac{3}{2}

2 x^{4} - x^{2} - 3 = 0

z^{4} = 121

x, x^{5} = a^{3}

x^{3} - 6 x^{2} + 12 x - 6 = 0

0 = - 0.015 x^{3} + 1.058 x

What are the solutions to the equation (x^2-3x)(2x+3)(x-1)=0 ?
The solutions to the equation (x^2-3x)(2x+3)(x-1)=0 are x=0,x=3,x=1,x=-3/2
Find the zeros of (x^2-3x)(2x+3)(x-1)=0
The zeros of (x^2-3x)(2x+3)(x-1)=0 are x=0,x=3,x=1,x=-3/2